00:01
In this problem, we are provided with the function f of x which equals to 4 times cos of x and x varies from 0 up to pi over 2.
00:16
We are asked to find out the area under the graph.
00:20
In subpart a, we are asked to use the right hand sum.
00:23
That is, we are asked to evaluate r4.
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So let us first find out del x.
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Del x equals to b minus a divided by n.
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So substituting b which is pi over 2 minus a which is 0 divided by n which is 4.
00:39
We obtain pi over 8.
00:41
Now let us consider the intervals.
00:44
We have 0 to pi over 8.
00:47
Pi over 8 up to pi over 4.
00:54
Pi over 4 up to 3 times pi over 8 and 3 times pi over 8.
01:01
Over 8 up to pi over 2.
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Now we need to evaluate the function at the right endpoints.
01:10
So we have f of pi over 8 to be equal to 3 .696 approximately.
01:16
F of pi over 4 equals to 2 .8 to 8 to 8 approximately f of 3 pi over 8 equals to 1 .531 approximately and f of pi over 2 .531 approximately and f of pi over 2 .5.
01:31
Equals to 0 since cost of pi over 2 is 0.
01:34
So let us consider the formula of r4 now.
01:38
R4 equals to del x times f of x1 plus f of x2 plus f of x3 plus f of x4.
01:49
Substituting the values we have pi over 8 times 3 .696 plus 2 .828 plus 1 .531 plus 1 .531 plus 0.
02:02
Adding these up and multiplying and dividing by pi and 8 respectively, we obtain 3 .1632...