Question

(a) Find the average value of the function $f(x) = -8\sqrt{x}$ on the interval $[0, 4]$. $f_{ave} =$ (b) Find $c$ such that $f_{ave} = f(c)$. $c = $

          (a) Find the average value of the function $f(x) = -8\sqrt{x}$ on the interval $[0, 4]$.
$f_{ave} =$
(b) Find $c$ such that $f_{ave} = f(c)$.
$c = $

(a) Find the average value of the function f(x) = -8√(x) on the interval [0, 4].
fave =
(b) Find c such that fave = f(c).
c =

Added by Bruce C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Khushbu Rani

01/29/2023

Step 1

To find the average value of a function on an interval [a,b], we use the formula: f_(ave) = (1/(b-a)) * ∫[a,b] f(x) dx In this case, a=0, b=4, and f(x)=-8√(x). So, we have: f_(ave) = (1/(4-0)) * ∫[0,4] -8√(x) dx f_(ave) = (1/4) * ∫[0,4] -8√(x) dx f_(ave) = (1/4) Show more…

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(a) Find the average value of the function f(x)=-8sqrt(x) on the interval 0,4. f_(ave )= (b) Find c such that f_(ave )=f(c). c= (a) Find the average value of the function f(x)=8/x on the interval [0, 4] fave= (b) Find c such that fave= f(c). C=