(a) Find the differential dy. y = cos(?x) dy = -?²cos ?x (b) Evaluate dy for the given values of x and dx. (Round your answer to three decimal places.) x = 1/3, dx = -0.01 dy = -0.03
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Step 1: Given that dy = -t^2 * cos(tx), we need to evaluate dy for the given values of x and dx. Show more…
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