(a) Find the normalization constant A for the wave function $\psi(x) = Axe^{-bx}$. (b) Find the normalization constant for the wave function $\psi(x) = Ae^{-b|x|}$.
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For the wave function ψ(x) = Axe−bx, this gives: ∫ from -∞ to ∞ |Axe−bx|² dx = 1 = ∫ from -∞ to ∞ A²x²e−2bx dx = 1 This integral can be solved by integration by parts or by looking it up in a table of integrals. The result is: A²/(4b³) = 1 So the normalization Show more…
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