00:01
We are told that we're going to be analyzing volumetrically carbonic acid.
00:08
And we have 50 milliliters of unknown concentration.
00:29
We dilute this to 200 mil liters.
00:41
Then we take 25 .00 millilitres of the 200 milons.
01:01
And we titrate with 0 .3125 milac.
01:12
Molarity, n -a -o -h to the m -point, and we do this four times titration 1, titration 2, titration 3, and titration 4.
01:27
We get the following for 24 .90, milliliters, 25 .55 milliliters, 24 .75 mil liters, 24 .75 mil liters, and 24 .75 mil liters, and 24 .8, and then we're going to answer some questions.
01:51
A, average volume used.
01:58
So i'm going to add 24 .90 milliliters plus 24 .75 milliliters plus 25 .5 milliliters plus 24 .80 milliliters.
02:18
And divide these by four.
02:20
This will equal.
02:21
24 .9 plus 25 .5 plus 24 .75 plus and i get, for heaven's sakes, exactly, 25 .00 milliliters.
02:39
That's my average.
02:41
Question b.
02:46
Number of moles of h2 -c -o -3 in the 25 .00 milliliters aliquots...