Question

(a) For what values of ( x ) is ( sum_{n=0}^{infty} frac{x^{n}}{n!} ) convergent? ( x geq 0 ) ( x<0 ) for all ( x ) none ( x leq 0 ) (b) What conclusion can be drawn about ( lim _{n ightarrow infty} frac{x^{n}}{n!} ) ? ( lim _{n ightarrow infty} x^{n} / n!=0 ) only for ( x<0 ) ( lim _{n ightarrow infty} x^{n} / n!=0 ) for all values of ( x ) ( lim _{n ightarrow infty} x^{n} / n!=0 ) only for ( x>0 ) No conclusion can be drawn. ( lim _{n ightarrow infty} x^{n} / n!=infty ) for all values of ( x )

          (a) For what values of ( x ) is ( sum_{n=0}^{infty} frac{x^{n}}{n!} ) convergent?
( x geq 0 )
( x<0 )
for all ( x )
none
( x leq 0 )
(b) What conclusion can be drawn about ( lim _{n 
ightarrow infty} frac{x^{n}}{n!} ) ?
( lim _{n 
ightarrow infty} x^{n} / n!=0 ) only for ( x<0 )
( lim _{n 
ightarrow infty} x^{n} / n!=0 ) for all values of ( x )
( lim _{n 
ightarrow infty} x^{n} / n!=0 ) only for ( x>0 )
No conclusion can be drawn.
( lim _{n 
ightarrow infty} x^{n} / n!=infty ) for all values of ( x )
        
Show more…
(a) For what values of ( x ) is ( sumn=0^infty fracx^nn! ) convergent?
( x geq 0 )
( x<0 )
for all ( x )
none
( x leq 0 )
(b) What conclusion can be drawn about ( lim n 
ightarrow infty fracx^nn! ) ?
( lim n 
ightarrow infty x^n / n!=0 ) only for ( x<0 )
( lim n 
ightarrow infty x^n / n!=0 ) for all values of ( x )
( lim n 
ightarrow infty x^n / n!=0 ) only for ( x>0 )
No conclusion can be drawn.
( lim n 
ightarrow infty x^n / n!=infty ) for all values of ( x )

Added by Joel E.

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University Calculus: Early Transcendentals
University Calculus: Early Transcendentals
Joel Hass, Christopher Heil, Przemyslaw… 4th Edition
Chapter 9
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Transcript

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00:01 So this is a power series okay uh you need to follow those um rules and it's actually it's known as the mclaren series for e to the x so this is actually e to the x and it converges for all x now we can also use the ratio test okay which is limit and goes to infinity infinity a n plus 1 over a n absolute value so this is going to be limit a n plus 1 is x to the n plus 1 which is x to the n times x and then m factorial which is m plus 1 times n factorial and then flips a n flips as this so this goes away this goes away this goes away so then we have limit of n goes to infinity absolute value of x and 1 over n plus 1 of course take absolute max absolute value of x out and then you get limit of 1 over n plus 1 and this goes to 0 right so then absolute value of x is 0 that means it's in for all x i mean the radius of convergence is infinity infinity negative infinity to infinity so for the first one a for all x and then b for all x again yeah again b b.
02:02 Limit is 0 for all x...
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