A force F(x) = (-5.0x^2 + 5.0x) N acts on a particle. (a) How much work (in J) does the force do on the particle as it moves from x = 4.0 m to x = 6.0 m? -203.33 (b) Picking a convenient reference point of the potential energy to be zero at x = 0, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules and x is in meters. Do not include units in your answer.) U(x) = 4/3 x^3 - 2x^2
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### Part (a): Calculating Work Done by the Force ** Show more…
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