Question

A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a diameter of 0.15 m, approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.

Name: a force of 250 n is applied to a hydraulic jack piston that is 002 m in diameter if the piston that supports the load has a diameter of 015 m approximately how much mass can be lifted by the 25542
Uploaded: 2022-06-08T16:38:35-08:00
Duration: 1 min 37 s
Channel: Ankur S
Description: a force of 250 n is applied to a hydraulic jack piston that is 002 m in diameter if the piston that supports the load has a diameter of 015 m approximately how much mass can be lifted by the 25542

          A force of 250 N is applied to a hydraulic jack piston that is
0.02 m in diameter. If the piston that supports the load has a
diameter of 0.15 m, approximately how much mass can be lifted by
the jack? Ignore any difference in height between the pistons.

Added by Alberto G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

06/08/2022

Step 1

Given that the diameter of the smaller piston is 0.02 m, the radius (r) is 0.01 m. Therefore, the area of the smaller piston is: A = π(0.01)^2 = 0.000314 m^2 Show more…

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A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a diameter of 0.15 m, approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.