53\) s
Time period on Planet X, \(T_{\text{X}} = 2.54\) s
Acceleration due to gravity on Earth, \(g_{\text{Earth}} = 9.8\) m/s\(^2\)
Using the formula:
\[
\frac{T_{\text{Earth}}}{T_{\text{X}}} = \sqrt{\frac{g_{\text{Earth}}}{g_{\text{X}}}}
\]
\[
\frac{1.53}{2.54}
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