00:01
Hello.
00:03
So for this question, what we need to do first is to work out the number of moles of gas that occupy 258 milliliters at stp, standard temperature pressure.
00:23
So the way we're going to do that is to, you know, remember that one mole of any ideal gas.
00:34
So one more of any ideal gas occupies a volume of 22 .4 liters, okay, at the stp.
01:06
Therefore, the moles of the gas that's going to be 0 .258.
01:16
So i changed this to liters, okay, just divided in a thousand.
01:24
Over 22 .4 liters for every mole, okay, as indicated here.
01:32
Okay, so that's going to give us a number of modes of 0 .011 f18 moved.
01:52
So what does this mean? so what this means is that a 0 .01, the number of most we just found, the gas has a mass.
02:10
So mass, 0 .6 grams.
02:23
And so with this information, we can get the molar mass now.
02:28
So the molar mass is going to be the mass over the moles.
02:48
That's number of moles.
02:49
So the mass is 0 .646 over the mole which is 0 .011 .18.
02:59
So the mona mass is going to be 56 .1 gram per mole.
03:10
So once we have this, we cannot work out the most of each element in one mole of the gas.
03:16
So let's talk about the mass of c in one more.
03:19
So m sub c in one more.
03:27
That's going to be 86 .63 percent times 56 .1 grampermower...