A geometric progression has a1=12, r=(1)/(2^'), an=(3)/(8^') ; find n and Sn.

Name: A geometric progression has a1=12, r=(1)/(2^'), an=(3)/(8^') ; find n and Sn.
Uploaded: 2024-11-14T15:24:24-08:00
Channel: Numerade
Description: A geometric progression has a1=12, r=(1)/(2^'), an=(3)/(8^') ; find n and Sn.

Question

A geometric progression has a1=12, r=(1)/(2^&#x27;), an=(3)/(8^&#x27;) ; find n and Sn.

Joshua Eastwood · Answer

This question says that we want to find seventh term, find A7, if A1 is 12 and R is one -half. S

Babita Kumari · Answer

This is question number 38. We have first term, A1 equal to 1 by 2, A12 equal to 1 ,000 and 24.

Angela Guo · Answer

We want to find a common ratio of a geometric sequence where the first term is 12, and the sixth

Sima Sarker · Answer

Here in this problem, we have to find the 12 term of the geometric sequence, 8, 4, 2, 1, and so

Danielle Mcclure · Answer

In this problem, we&#x27;re asked to find the 10th term of this geometric sequence. So something to n

Question

A geometric progression has \( a_{1}=12, r=\frac{1}{2^{\prime}}, a_{n}=\frac{3}{8^{\prime}} ; \) find \( n \) and \( S_{n} \).

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