Question

a. Graph the functions f(x) = (x)/3 and g(x) = 3 + (12)/x together to identify the values of x for which (x)/3 > 3 + (12)/x. b. Confirm your findings in part (a) algebraically. Each graph is shown in a [-20, 20] by [-8, 8] viewing window. What are the values of x for which (x)/3 > 3 + (12)/x? (Type your answer in interval notation.) b. When the given inequality is rewritten so that there is a zero on the right side and the left side is a single rational expression, the result is > 0. The numerator is zero if x = and the denominator is zero if x = ◻. These values divide the real line into intervals. Using a test value from each interval confirms that (x)/3 > 3 + (12)/x for values of x on (Use a comma to separate answers as needed. Type your answer in interval notation.) X 12 12 Y b. Confirm your findings in part a algebraically Each graph is shown in a [-20, 20] by [-8, 8] viewing window 12 -3, 0 U 12, o Type your answer in interval notation. b. When the given inequality is rewritten so that there is a zero on the right side and the left side is a single rational expression, the result is > 0. The numerator is zero if x = and the denominator is zero if x = These values divide the real line into intervals. Using a test value from each interval (Use a comma to separate answers as needed. Type your answer in interval notation.)

          a. Graph the functions f(x) = (x)/3 and g(x) = 3 + (12)/x together to identify the values of x for which (x)/3 > 3 + (12)/x.
b. Confirm your findings in part (a) algebraically.
Each graph is shown in a [-20, 20] by [-8, 8] viewing window.
What are the values of x for which (x)/3 > 3 + (12)/x?
(Type your answer in interval notation.)
b. When the given inequality is rewritten so that there is a zero on the right side and the left side is a single rational expression, the result is > 0. The numerator is zero if x = and the denominator is zero if x = ◻. These values divide the real line into intervals. Using a test value from each interval confirms that (x)/3 > 3 + (12)/x for values of x on
(Use a comma to separate answers as needed. Type your answer in interval notation.)
X
12
12
Y
b. Confirm your findings in part a algebraically
Each graph is shown in a [-20, 20] by [-8, 8] viewing window
12
-3, 0 U 12, o Type your answer in interval notation.
b. When the given inequality is rewritten so that there is a zero on the right side and the left side is a single rational expression, the result is > 0. The numerator is zero if x = and the denominator is zero if x = These values divide the real line into intervals. Using a test value from each interval
(Use a comma to separate answers as needed. Type your answer in interval notation.)

a graph the functions fx x3 and gx 3 12x together to identify the values of x for which x3 3 12x b confirm your findings in part a algebraically each graph is shown in a 20 20 by 8 8 viewing 04858

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