A high-speed density drill rotating at 50,000 rpm is 1 mm in diameter. How far can it throw a 40 μm piece of your tooth? Assume the tooth particle is spherical and has a density of 2 g/cm³.
Added by Nichole N.
Step 1
The radius of the drill is r = 0.5 mm = 0.0005 m. The angular velocity is ω = 50,000 rpm = 50,000 × (2π/60) rad/s = 5,236 rad/s. v = rω = 0.0005 m × 5,236 rad/s = 2.618 m/s Show more…
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