A highly excited atom of hydrogen makes a transition from the n = 12 to the n = 11 state and emits a photon. What is the energy of this photon in joules?
Added by Grace H.
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The energy of a hydrogen atom in a particular state is given by the formula E = -13.6 eV/n^2, where n is the principal quantum number. Show more…
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(part a) A highly excited atom of hydrogen makes a transition from the n = 13 to the n = 12 state and emits a photon. What is the energy of this photon in joules? (part b) What is the wavelength in meters of the photon emitted when this highly excited hydrogen atom of hydrogen makes its transition from the n = 13 to the n = 12 state?
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