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What is the energy of a photon that, when absorbed by a hydrogen atom, could cause an electronic transition from (a) the $n=2$ state to the $n=5$ state and (b) the $n=4$ state to

the $n=6$ state?

a) 2.86 $\mathrm{cV}$

b) 0.472 $\mathrm{eV}$

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In this exercise, we have to calculate the energies of Fulton's that could be absorbed by a hydrogen atom and caused transitions from in question A from the second to the fifth energy level and in question, be from the fourth to the sixth. Enter your level. Okay, so, toe, answer each one of these questions. The first thing I have to notice it's that the energy of the photon is to have a gamma from conservation of energy has to be equal to the difference of energy between the final energy level. Yes, and the initial energy of level e I. Okay, And given that the energy off Ah, the energy off the IMF level of the hydrogen atom writing it here in blue is minus 13.6 divided by and square electoral votes than this means that the gamma is equal to 13.6 times one over, and I squared. And I is the initial energy level minus and F square. Okay, this is the energy of that. The full time has to have. So now all we have to do is to, uh, plug and I in enough in question questions. A and B. Okay, so in question. A. We have an I is to. That's initial energy level in the final energy level is five. So yeah, E gamma is 13.6 votes times 1/2 square. So that's four. Mine is one over for five squared, which is 25. So this is equal to 2.856 electoral votes in question be we have that Gamma is equal to 13.6 times and I squint one over and I square and I is four for question be NF six. So have won over Foursquare's. That's 1/16 over miners, one over seeing square. That's whenever 36. So this is equal to zero point 47472 electoral votes. Okay, and this concludes the

Universidade de Sao Paulo