"A horizontal force of 5 N is required to maintain a velocity of 2 m/s for a block of 10 kg mass sliding over a rough surface. The work done by this force in one minute is (a) 600 J (b) 60 J (c) 6 J (d) 6000 J"
Added by Barry B.
Step 1
Step 1: Identify the given values in the problem: - Force (\( F \)) = 5 N - Velocity (\( v \)) = 2 m/s - Mass (\( m \)) = 10 kg - Time (\( t \)) = 1 minute = 60 seconds Show more…
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A horizontal force of $5 N$ is required to maintain a velocity of $2 \mathrm{~m} / \mathrm{s}$ for a block of $10 \mathrm{~kg}$ mass sliding over a rough surface. The work done by this force in one minute is (a) $600 J$ (b) $60 J$ (c) $6 J$ (d) $6000 J$
A block of mass $2 \mathrm{~kg}$ initially at rest moves under the action of an applied horizontal force of $6 \mathrm{~N}$ on a rough horizontal surface. The coefficient of friction between block and surface is $0.1 .$ The work done by the applied force in $10 \mathrm{~s}$ is (Take $g=10 \mathrm{~m} \mathrm{~s}^{-2}$ ) (a) $200 \mathrm{~J}$ (b) $-200 \mathrm{~J}$ (c) $600 \mathrm{~J}$ (d) $-600 \mathrm{~J}$
A body of mass 5 Kg initially at rest is moved by a horizontal force of 2 N on a smooth horizontal surface. The work done by the force in 10 s is A. 20 J B. 30 J C. 40 J D. 60 J
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