00:02
Welcome to this numerary tutorial.
00:04
So we can start with part a and the flow type is divergent as opposed to convergent because the cross -sectional area is increasing with respect to directional flow.
00:23
As for part b, you can use the equation of fluid continuity, which is equal to a1 times v1.
00:39
Is equal to a2 times v2.
00:42
The viscosity move specification in this case because the mass flow is irrelevant, can be ignored, but the row value, the density of water 999 .7 kilograms per cubic meter will be applicable to solving the problem.
01:06
But first, we must compute the v2 output flow at the larger cross -sectional area.
01:17
So we start with diameter 1 and convert the diameter to meters value, followed by solving for the cross -sectional area at a1, which is 0 .113 square meters.
01:37
And then we continue and do the same for diameter 2.
01:43
So we have established a1 and a2 values.
01:52
So using the equation of fluid continuity, we can then solve for v2, the output, velocity, at the larger cross -sectional area, which is equal to 6 .4 meters per second...