Question

A horizontal pipe has an abrupt expansion from D1 = 5 cm to D2 = 10 cm. The water velocity in the smaller section is 8 m/s and the flow is turbulent. The pressure in the smaller section is P1 = 450 kPa. Taking the kinetic energy correction factor to be 1.06 at both the inlet and the outlet. Let density of water to be p = 1000 kg/m3. What is the downstream velocity the water? a) 2 m/s b) 8 m/s c) 4 m/s d) 32 m/s The engineer needs to find the loss for the coefficient for sudden expansion in order to calculate the head loss. Calculate the loss for the coefficient. a) 0.2 b) 0.596 c) 1.06 d) 0.155

Name: a horizontal pipe has an abrupt expansion from d1 5 cm to d2 10 cm the water velocity in the smaller section is 8 ms and the flow is turbulent the pressure in the smaller section is p1 450 k 80727
Uploaded: 2023-06-09T08:00:11-08:00
Duration: 4 min 29 s
Channel: Supreeta N
Description: a horizontal pipe has an abrupt expansion from d1 5 cm to d2 10 cm the water velocity in the smaller section is 8 ms and the flow is turbulent the pressure in the smaller section is p1 450 k 80727

          A horizontal pipe has an abrupt expansion from D1 = 5 cm to D2 =
10 cm. The water velocity in the smaller section is 8 m/s and the
flow is turbulent. The pressure in the smaller section is P1 =
450 kPa. Taking the kinetic energy correction factor to be
1.06 at both the inlet and the outlet. Let density of water to be
p = 1000 kg/m3.
What is the downstream velocity the water?
a) 2 m/s
b) 8 m/s
c) 4 m/s
d) 32 m/s
The engineer needs to find the loss for the coefficient
for sudden expansion in order to calculate the head loss.
Calculate the loss for the coefficient.
a) 0.2
b) 0.596
c) 1.06
d) 0.155

Added by Edward W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

06/09/2023

Step 1

Since the pipe is horizontal, the cross-sectional area is proportional to the diameter squared: A1 = π(D1/2)^2 = 0.196 m^2 A2 = π(D2/2)^2 = 0.785 m^2 Using the given values, we can solve for V2: V2 = (A1V1)/A2 = (0.196*8)/0.785 = 1.98 m/s So the answer is (a) Show more…

Show all steps

Thanks for your feedback!

A horizontal pipe has an abrupt expansion from D1 = 5 cm to D2 = 10 cm. The water velocity in the smaller section is 8 m/s and the flow is turbulent. The pressure in the smaller section is P1 = 450 kPa. Taking the kinetic energy correction factor to be 1.06 at both the inlet and the outlet. Let density of water to be p = 1000 kg/m3. What is the downstream velocity the water? a) 2 m/s b) 8 m/s c) 4 m/s d) 32 m/s The engineer needs to find the loss for the coefficient for sudden expansion in order to calculate the head loss. Calculate the loss for the coefficient. a) 0.2 b) 0.596 c) 1.06 d) 0.155