A hot-air balloon rises vertically from the ground so that its height after t s is given by the following function. h = 1 2 t2 + 1 2 t ft where (0 ≤ t ≤ 60) (a) What is the height (in ft) of the balloon at the end of 35 sec? ft (b) What is the average velocity (in ft/sec) of the balloon between t = 0 and t = 35? ft/sec (c) What is the velocity at time t? v(t) = What is the velocity (in ft/sec) at the end of 35 sec? ft/sec
Added by Brian V.
Step 1
Substitute t = 35 into the equation: h = 1/2(35)^2 + 1/2(35) Calculate: h = 1/2(1225) + 1/2(35) = 612.5 + 17.5 = 630 ft Therefore, the height of the balloon at the end of 35 seconds is 630 ft. Show more…
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