Question

A hot-air balloon rises vertically from the ground so that its height after t s is given by the following function. h = 1/2 t^2 + 1/2 t ft where (0 ? t ? 60) (a) What is the height (in ft) of the balloon at the end of 39 sec? ft (b) What is the average velocity (in ft/sec) of the balloon between t = 0 and t = 39? ft/sec (c) What is the velocity at time t? v(t) = What is the velocity (in ft/sec) at the end of 39 sec? ft/sec

          A hot-air balloon rises vertically from the ground so that its height after t s is given by the following function.
h = 1/2 t^2 + 1/2 t ft where (0 ? t ? 60)
(a) What is the height (in ft) of the balloon at the end of 39 sec?
ft
(b) What is the average velocity (in ft/sec) of the balloon between t = 0 and t = 39?
ft/sec
(c) What is the velocity at time t?
v(t) =
What is the velocity (in ft/sec) at the end of 39 sec?
ft/sec

A hot-air balloon rises vertically from the ground so that its height after t s is given by the following function.
h = 1/2 t^2 + 1/2 t ft where (0 ? t ? 60)
(a) What is the height (in ft) of the balloon at the end of 39 sec?
ft
(b) What is the average velocity (in ft/sec) of the balloon between t = 0 and t = 39?
ft/sec
(c) What is the velocity at time t?
v(t) =
What is the velocity (in ft/sec) at the end of 39 sec?
ft/sec

Added by Raquel R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Darshan Maheshwari

11/05/2021

Step 1

Step 1: Substitute t = 39 into the height function h = 42t^2 to find the height of the balloon at the end of 39 seconds. Show more…

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A hot-air balloon rises vertically from the ground so that its height after t s is given by the following function: h = 1/2 t^2 + 1/2 t ft where (0 ≤ t ≤ 60) (a) What is the height (in ft) of the balloon at the end of 39 sec? (b) What is the average velocity (in ft/sec) of the balloon between t = 0 and t = 39? (c) What is the velocity at time t? v(t) = What is the velocity (in ft/sec) at the end of 39 sec?