A hydraulic lift has a small piston with a diameter 5.0 cm piston and the large piston with a diameter of 25 cm. What force must be applied on the small piston in order to lift a car on the large piston that weighs 13,000 N?
Added by Joseph S.
Step 1
We need to find the area of both pistons. - The area of the small piston (A1) = πr1^2 = π(2.5 cm)^2 = 19.63 cm^2 - The area of the large piston (A2) = πr2^2 = π(12.5 cm)^2 = 490.87 cm^2 Show more…
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