Question

A hydrogen atom emits a photon that has momentum 6.813 × 10-27 kg·m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-19 C.

Name: a hydrogen atom emits a photon that has momentum 6813 10 27 kgms this photon is emitted because the electron in the atom falls from a higher energy level into the n 1 level what is the quant 14057
Uploaded: 2022-06-24T07:01:04-08:00
Duration: 2 min 11 s
Channel: Shyam P
Description: a hydrogen atom emits a photon that has momentum 6813 10 27 kgms this photon is emitted because the electron in the atom falls from a higher energy level into the n 1 level what is the quant 14057

          A hydrogen atom emits a photon that has momentum 6.813 × 10-27
kg·m/s. This photon is emitted because the electron in the atom
falls from a higher energy level into the n = 1 level. What is the
quantum number of the level from which the electron falls? Use
values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602
× 10-19 C.

Added by William S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shyam P

06/24/2022

Step 1

Step 1: Use the formula for momentum in terms of quantum number and constants: \(p = \frac{n h}{2\pi}\) Show more…

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A hydrogen atom emits a photon that has momentum 6.813 × 10-27 kg·m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-19 C.