00:01
So in this question we have ground state hydrogen atom, absorbing a photon of energy 13 .06 ev.
00:19
And subsequently it undergoes a quantum jump.
00:23
We are given that this quantum jump has delta n equals to 2, right? so it's quantum number changes by 2, and it emits a photon.
00:33
We want to know what is the energy of this photon.
00:36
And first of all we will need to find what is this energy quantum state.
00:43
So to find that we make use of the fact that the energy of any states in the hydrogen atom can be written as such, where n is the quantum number.
00:58
So for it to absorb an energy of 13 .06 ev, the corresponding energy, must be 13 .6 ev away from the ground state.
01:16
So, en minus e1 must be 13 .06 ev.
01:26
We just have to substitute en from here and e1 from here.
01:46
We do some manipulation...