A hydrogen atom in the ground state absorbs a 12.75 eV photon. Immediately after the absorption, the atom undergoes a quantum jump to the next-lowest energy level. What is the wavelength of the photon emitted in this quantum jump?
Added by Justin N.
Step 1
Given that the hydrogen atom absorbed a 12.75 eV photon, we convert this energy to joules by using the conversion factor 1 eV = 1.602 x 10^-19 J. 12.75 eV * 1.602 x 10^-19 J/eV = 2.04 x 10^-18 J Show more…
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