00:01
Anytime we use an enzyme, an enzyme is a biological catalyst, and a catalyst always lowers the activation energy.
00:08
So quickly, we can get rid of any statement that says the enzyme raises the activation energy.
00:15
So now we're just down to the answers that state the enzyme lowers the activation energy, but by how much? well, to do that, we'll recognize that k2 is 10 ,000 times.
00:30
K1, where k2 is the rate constant when we have the catalyst or the enzyme present.
00:41
According to the uranus equation, k1 will be equal to a, the frequency factor, multiplied by e to the negative ea over rt.
00:52
K2 will be equal to the same thing but for its activation energy, but k2 is equal to 10 ,000 times k1.
01:06
Again, k2 is when the enzyme is present, when the enzyme is present, the activation energy is lower, resulting in a faster reaction or a larger k value, 10 ,000 times k1 that doesn't have the enzyme.
01:24
If we divide these two equations, the a's will cancel, the k -1s will cancel, and we'll get 0 .001 is equal to, this ratio, if we take the natural log of both sides, using our natural log rules, we get negative 9 .21...