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Hi.
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Here in this given problem, this is the smooth wall, frictionless wall.
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This is the rough floor and that is the ladder put like this.
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This is the upper end of the ladder a, lower end b, the normal force of reaction at the upper end due to the wall that is represented as fw and normal force of the ground.
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Over the lower end at the lower end of the ladder that is f g this end lower end is having a tendency to slip towards right so there will be a force of friction static friction towards left this is the center of mass of the ladder so weight of the ladder w, that will be acting vertically downward at this center of mass c.
01:07
Length of the ladder means a, b.
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This is given as 10 meter.
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This angle theta over here, that is 50 degree.
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And weight of the ladder, this is 50 newton.
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Now, as in equilibrium, in static equilibrium, equilibrium, there is no net force along vertical...