00:01
Hi, i'm david and i'm here to help me answer your question.
00:04
Now let me bring up your question here.
00:06
In the question here, a lecture hall has 236 with folding amp tablets, 39 which are designed for the left handers.
00:17
So if we summarize the question here, we will have total of the 29 and then we have the 39 of them will be from the left hander.
00:32
And we put as an l and then we have the the rest could be 2 -30 minus 29 equal to the 201 will be the right -hander and now we will have the average size on the class there will be the 204 so we have the n equal to the 204 and we have the percentage on the left -handed b equal to the 0 .1 -2 that will be from the left -handed and now one is a probability that a right -handed student in one of this class is forced to use a left -tie -am tablet.
01:17
So if we call the x equal to the number of the left -handed.
01:27
So maybe it will call it the right -handed to make it easier students.
01:37
And then we see x it will follow by the binomial with the n equals 2 of 4.
01:42
B now will be the right -handed, so it will be 1 minus 0 .1 -2, so it will equal to the 0 .88.
01:50
And the question asks me to find the probability that the number of the right -handed students will be greater than the 2 -01.
02:00
So it means that one to find probability of the x will be greater than the 201.
02:05
And to find this probability here, it's followed by the polynomial.
02:10
And let me remind you the power about the binomial...