00:01
In this exercise, we are given a scenario where there's a lecture hall with 200 seats that have folding arm tablets, 30 of which are designed for left -handers.
00:09
And we're also told that the typical class size in that lecture hall is 188 people.
00:15
And we can assume that 13 % of students are left -handed.
00:19
And we are asked to calculate the probability that a right -handed student in one of the classes must use the lefty arm tablet.
00:27
So there's a few numbers here.
00:29
So we have an auditorium with 200 seats.
00:32
It is important to note that our sample size is 188 because that's the number of people that typically go to this class.
00:41
If we're looking for a situation where a right -hander must use a left -handed seat or arm tablet, that means there has to be more right -handed people than there are right -handed arm tablets.
00:55
We're told there are 200 seats and 30 are designed for left -handers, which means that we have 200 minus 30 or 70 designed for right -handers.
01:08
It's 170.
01:13
So it seems easier to approach this problem by defining a success as a student being right -handed, in which case the probability success is 100 minus 13%, which is 0 .87.
01:28
And we can consider each student to be a bernoulli trial, where there's success or failure.
01:33
Success is being right -handed.
01:34
The probability of success is constant at 0 .87, and each student's outcome is independent from the other students.
01:47
So if we can assume that these are bernoulli trials, and we define the random variable x as the number of right -handers in 188 students, then x is a binomial random variable based on 188 trials and probability of success of 0 .87.
02:22
Computationally it will be easier to express this or to approximate this with the normal distribution.
02:28
So first we want to check to see if n times p and n times q are both at least as big as 10...