00:01
Hello students, so a light ray is going from air to glass to water.
00:11
So we know the refractive index of air is equal to 1, that of glass equal to 1 .5 and that of water is equal to 1 .33.
00:25
So first of all, we want to find angle of of refraction in glass.
00:45
So they are given the incident angle i equal to 20 degree.
00:52
And we know the equation that is n i.
00:58
Sin theta i is equal to nr sine theta r.
01:03
So since this 20 degree is the theta i.
01:09
And n i is equal to n a is equal to one n r is equal to n g is equal to 1 .5 so now we can simply substitute it here that is 1 into sine 20 degree is equal to 1 .5 into sine of theta r so theta r is equal to of sine 20 divided by 1 .5.
02:02
So therefore, theta r will be 16 .36 degree.
02:12
And the next one, ankle of refraction of water.
02:27
That's what we want to find...