Question
An aquarium filled with water has flat glass sides whose index of refraction is $1.56 .$ A beam of light from outside the aquarium strikes the glass at a $43.5^{\circ}$ angle to the perpendicular (Fig. $32-49$ ). What is the angle of this light ray when it enters $(a)$ the glass, and then (b) the water?(c) What would be the refracted angle if the ray entered the water directly?
Step 1
The formula is given by: \[n_1 \sin(\theta_1) = n_2 \sin(\theta_2)\] where \(n_1\) and \(n_2\) are the indices of refraction for the two media, and \(\theta_1\) and \(\theta_2\) are the angles of incidence and refraction, respectively. Show more…
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(II) An aquarium filled with water has flat glass sides whose index of refraction is $1.56 .$ A beam of light from outside the aquarium strikes the glass at a $43.5^{\circ}$ angle to the perpendicular (Fig. 49). What is the angle of this light ray when it enters $(a)$ the glass, and then $(b)$ the water? $(c)$ What would be the refracted angle if the ray entered the water directly?
An aquarium filled with water has flat glass sides whose index of refraction is 1.54. A beam of light from outside the aquarium strikes the glass at a 43.5° angle to the perpendicular (Fig. 23-56). What is the angle of this light ray when it enters? (a) The glass, and then (b) The water? (c) What would be the refracted angle if the ray entered the water directly?
(II) An aquarium filled with water has flat glass sides whose index of refraction is 1.54. A beam of light from outside the aquarium strikes the glass at a 43.5$^\circ$ angle to the perpendicular (Fig. 23-56). What is the angle of this light ray when it enters (a) the glass, and then (b) the water? (c) What would be the refracted angle if the ray entered the water directly? FIGURE 23–56 Problem 32. (FIGURE CAN'T COPY)
LIGHT: GEOMETRIC OPTICS
Refraction: Snell's Law
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