Question

An aquarium filled with water has flat glass sides whose index of refraction is 1.54. A beam of light from outside the aquarium strikes the glass at a 43.5° angle to the perpendicular (Fig. 23-56). What is the angle of this light ray when it enters? (a) The glass, and then (b) The water? (c) What would be the refracted angle if the ray entered the water directly?

Name: an aquarium filled with water has flat glass sides whose index of refraction is 154 a beam of light from outside the aquarium strikes the glass at a 435 angle to the perpendicular fig 23 56 69802
Uploaded: 2022-12-12T10:04:21-08:00
Duration: 2 min 15 s
Channel: Sri K
Description: an aquarium filled with water has flat glass sides whose index of refraction is 154 a beam of light from outside the aquarium strikes the glass at a 435 angle to the perpendicular fig 23 56 69802

          An aquarium filled with water has flat glass sides whose index of refraction is 1.54. A beam of light from outside the aquarium strikes the glass at a 43.5° angle to the perpendicular (Fig. 23-56). What is the angle of this light ray when it enters? (a) The glass, and then (b) The water? (c) What would be the refracted angle if the ray entered the water directly?

Added by Carl T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

12/12/2022

Step 1

Given: n1 = 1 (air), n2 = 1.54 (glass), θ1 = 43.5° Snell's Law states: n1*sin(θ1) = n2*sin(θ2) Substitute the values: 1*sin(43.5°) = 1.54*sin(θ2) Solve for θ2: sin(θ2) = (1*sin(43.5°))/1.54 θ2 = sin^(-1)((1*sin(43.5°))/1.54) θ2 ≈ 26.55° Show more…

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An aquarium filled with water has flat glass sides whose index of refraction is 1.54. A beam of light from outside the aquarium strikes the glass at a 43.5° angle to the perpendicular (Fig. 23-56). What is the angle of this light ray when it enters? (a) The glass, and then (b) The water? (c) What would be the refracted angle if the ray entered the water directly?