A lightbulb designed to operate in a 90V circuit has a resistance of 226Omega . At what rate does the bulb use electric energy w A lightbulb designed to operate in a 90 V circuit has a resistance of 226Q.At what rate does the bulb use electric energy
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P = (90V)^2 / 226Ω P = 8100V^2 / 226Ω P = 35.84 W Show more…
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