A liquid of density ( ho) in a container weighs (W). A cubic...

A liquid of density ( ho) in a container weighs (W). A cubic block of side (L) and density ( ho_b> ho) is tied to a string and is completely submerged into the liquid. If (g) is the acceleration due to gravity, what is the new weight of the composite system as registered by the weighing machine below the container? A. (W+( ho_b- ho)gL^3) B. (W+ ho_b g L^3) C. (W+( ho- ho_b)gL^3) D. (W+ ho g L^3)

A partly filled beaker of water sits on a scale, and its weight is $2.30 \mathrm{~N}$. When a piece of metal suspended from a thread is totally immersed in the beaker (but not touching bottom), the scale reads $2.75 \mathrm{~N}$. What is the volume of the metal? The water exerts an upward buoyant force on the metal. According to Newton's Third Law of action and reaction, the metal exerts an equal downward force on the water. It is this force that increases the scale reading from $2.30 \mathrm{~N}$ to $2.75 \mathrm{~N}$. Hence the buoyant force is $2.75-2.30=0.45 \mathrm{~N}$. Then, because $F_{B}=$ weight of displaced water $=\rho_{w} g V=\left(1000 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)(V)$ we have the volume of the displaced water, and of the piece of metal, namely, $$ V=\frac{0.45 \mathrm{~N}}{9810 \mathrm{~kg} / \mathrm{m}^{2} \cdot \mathrm{s}^{2}}=46 \times 10^{-6} \mathrm{~m}^{3}=46 \mathrm{~cm}^{3} $$

Question

Please give Ace some feedback