A liquid with a specific gravity of 0.90 is flowing in a 200-mm diameter pipe with a velocity of 12 m/s. Determine the following: (a) volume flow rate [in m3/s] (b) mass flow rate [in kg/s] (c) weight flow rate [in N/s]
Added by Hugo R.
Step 1
The area of the pipe can be calculated using the formula A = Ļ*(D/2)^2, where D is the diameter of the pipe. So, A = Ļ*(0.2/2)^2 = 0.0314 m^2. Then, Q = 12 m/s * 0.0314 m^2 = 0.377 m^3/s. Show moreā¦
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