A magnet produces a 0.30 T field between its poles, directed to the east. A dust particle with c

Question

Khoobchandra Agrawal · Accepted Answer

Step 1: Calculate the magnetic force on the dust particle using the formula F = qvBsinθ, where q

A magnet produces a 0.30 T field between its poles, directed to the east. A dust particle with charge $q=-8.0 \times 10^{-18} \mathrm{C}$ is moving straight down at $0.30 \mathrm{cm} / \mathrm{s}$ in this field. What is the magnitude and direction of the magnetic force on the dust particle?