00:01
Hello and welcome to this video solution of numerate.
00:04
Here it's given that a uniform magnetic field of 0 .5 tesla is directed to the north right.
00:10
So the magnetic field b is 0 .5 tesla and it is directed to the north what we can take it in the y axis right.
00:19
So let's say this x axis is towards east and the y axis is towards north right.
00:29
At some instant a particle with charge q which is equal to 0 .02 mu coulomb is moving with a velocity of v which is 2 meters per second in a direction which is 30 degree north of east right.
00:47
So this is the velocity vector right.
00:55
Now what is the magnitude of the magnetic force on the charged particle right and what is the direction of this force.
01:04
So what you can do is you can resolve this velocity into two components along the x and y right.
01:11
So v vector will be equal to 2 sine theta i cap plus cos theta j cap right.
01:26
So it's a 2 sine 30 theta is 30 degrees right i cap plus 2 cos 30 j cap right and this is equal to i cap plus root 3 j cap right.
01:53
So this is the velocity vector.
01:54
Now to calculate the force f what you can do is you can have q times of v cross b right.
02:06
It's a cross product you have to calculate.
02:09
So the charge is 0 .02 mu coulomb right...