00:02
Hello, for this question, we applied the principle of moments, which states that the sum of clockwise moments about a point equals the sum of anti -clockwise moments about the same point, provided the system or body is in equilibrium so we can reproduce the forearm this way we represent the ball by this arrow it weighs 162 newtons and the weight of the arm itself acts at the center of mass it is 22 newtons the pivot with the that as p, that is where the elbow is.
01:30
And we identify the distance of each force.
01:33
Yes, the last force we need to add is the flexer, the force in the flexer muscle, which is going to keep the ball up.
01:45
So we identify the distance of each force from the pivot, the perpendicular distance of each force from the pivot.
01:55
So 0 .330 for the ball.
02:06
The center of mass is at a distance of 0 .10 sorry 0 .14 from the pivot and we get that 0 .14 by adding from the diagram by adding 0 .015 and 0 .0 890 0 0 .0 .0 .15 plus 0 .05 plus 0 .0151 plus 0 .080 gives us this over here.
03:12
Now, the force f is also at a distance of 0 .0510...