00:01
In this question, the cost function is given by c equals to 0 .3x square plus 9000.
00:10
Now, here let t be the time, t be the time in months, t be the time in months and the production and the production is changing at a rate of, production is changing at the rate of 16 units, 16 units per month is given, per month is given.
00:49
So, therefore, dx upon dt, dx upon dt is given as 16.
00:58
So, differentiating the cost function, differentiating the cost function, cost function with respect to time, function with respect to time.
01:14
So, therefore, dcx upon dt which is equals to, this will be equals to 0 .3 into 2x dx upon dt plus derivative of 9000, that will be 0, because it is a constant term...