a mass m slides upward along a rough plane surface inclined at angle theta 014 in radians to the

Name: a mass m slides upward along a rough plane surface inclined at angle theta 014 in radians to the horizontal initially the mass has a speed v0 v 0 228 ms before it slides a distance l 10 m u 45884
Uploaded: 2022-07-31T20:10:09-08:00
Duration: 2 min 2 s
Channel: Ivan Kochetkov
Description: a mass m slides upward along a rough plane surface inclined at angle theta 014 in radians to the horizontal initially the mass has a speed v0 v 0 228 ms before it slides a distance l 10 m u 45884

Step 1: Draw a free body diagram of the mass M on the inclined plane. The forces acting on the m

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Question

A mass M slides upward along a rough plane surface inclined at an angle Theta: Î˜ = 0.14 radians to the horizontal. Initially, the mass has a speed V_0 = 2.28 m/s before it slides a distance L = 1.0 m up the incline. After sliding this distance, the new speed of the mass is V_0 / 3 measured in m/s. What is the acceleration of the sliding mass? (Positive denotes acceleration up the incline; negative denotes acceleration down the incline.)

          A mass M slides upward along a rough plane surface inclined at an angle Theta: Î˜ = 0.14 radians to the horizontal. Initially, the mass has a speed V_0 = 2.28 m/s before it slides a distance L = 1.0 m up the incline. After sliding this distance, the new speed of the mass is V_0 / 3 measured in m/s. What is the acceleration of the sliding mass? (Positive denotes acceleration up the incline; negative denotes acceleration down the incline.)

Added by Jennifer G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

07/31/2022

Step 1

The forces acting on the mass are the gravitational force (mg) acting downward, the normal force (N) acting perpendicular to the surface, and the frictional force (f) acting parallel to the surface in the opposite direction of motion. Show more…

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A mass M slides upward along a rough plane surface inclined at an angle Theta: Î˜ = 0.14 radians to the horizontal. Initially, the mass has a speed V_0 = 2.28 m/s before it slides a distance L = 1.0 m up the incline. After sliding this distance, the new speed of the mass is V_0 / 3 measured in m/s. What is the acceleration of the sliding mass? (Positive denotes acceleration up the incline; negative denotes acceleration down the incline.)