A mixture of 142.8 g of Cl2 and 31.2 g of P reacts completely to form PCl3 and PCl5. Find the mass of PCl5 produced.
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Step 1
Given: - Mass of Cl2 = 142.8 g - Mass of P = 31.2 g Molar mass of Cl2 = 35.5 g/mol + 35.5 g/mol = 71 g/mol Molar mass of P = 31 g/mol Moles of Cl2 = 142.8 g / 71 g/mol = 2 mol Moles of P = 31.2 g / 31 g/mol = 1 mol Show more…
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