00:01
In this problem, we want to find the direction and the magnitude of the velocity after some object has moved 12 meters in the x -axis with this initial velocity and this acceleration.
00:15
So let's begin by finding the x and y components of velocity.
00:20
We know that velocity squared is equal to initial velocity plus two times the acceleration times the displacement.
00:32
And we know the displacement in the x -axis.
00:35
So let's use this equation to find, or oops, this should be square.
00:40
Yeah.
00:41
Let's use this equation to find our x quantities.
00:46
So the velocity in the x -axis is going to be equal to the square root of the initial velocity in the x -axis plus two times the acceleration times the displacement.
01:00
And we have all this information.
01:02
We have the initial velocity over here.
01:05
That's four squared plus two times the acceleration in the x -axis which is five and then we are told that the displacement is 12 meters along the x -axis so this velocity is going to give us roughly 11 .7 meters per second now we cannot use the same equation to find the y component because we don't know the displacement in the y -axis and it would probably take a while to solve for the displacement so it's easier to find the time it took to an object to move to this speed in that displacement.
01:49
So let's use this equation to find that time instead.
01:56
Let's use some blue.
01:58
We can say that the displacement in the x -axis is equal to one -half times the velocity in the x -axis plus the velocity, the final velocity in the x -axis times the time.
02:14
So here we have our time...