A molecule which has absorbed a photon of energy in the visible range could move from the excited electronic state (S1) to a highly excited vibrational level of the ground state (So) with the same energy. What is this process called? a. fluorescence b. internal conversion c. vibrational relaxation d. intersystem crossing
Added by Lee F.
Close
Step 1
This process is known as vibrational relaxation. Show more…
Show all steps
Your feedback will help us improve your experience
Joshua Klint and 72 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Which of the following best describes the process of fluorescence? a. Molecules emit a photon at lower energy when excited electrons return to the ground state. b. Atoms emit a photon when the electrons are excited. c. Molecules emit a photon when the electrons are excited. d. Molecules emit a photon at the same energy when excited electrons return to the ground state. e. Molecules emit a photon at higher energy when excited electrons return to the ground state.
Asami E.
Which of the following is NOT an electronic state deactivation process? A. absorbance B. vibrational relaxation C. fluorescence D. dissociation
Ronald P.
Molecules have low-energy vibration modes, and they can make transitions from one such state to another that result in the emission of infrared radiant energy. Suppose two such states are separated by $0.015 \mathrm{eV}$, and the molecule descends in energy from the higher to the lower. Determine the wavelength of the photon that would be emitted.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD