Question

A monatomic ideal gas that is initially at a pressure of 1.52×105 Pa and with a volume of 8.10×10−2 m3 is compressed adiabatically to a volume of 4.50×10−2 m3. Part A What is the final pressure? P = Pa Part B How much work is done by the gas during the compression? W = J Part C What is the ratio of the final temperature of the gas to its initial temperature? Tf/Ti =

Name: a monatomic ideal gas that is initially at a pressure of 152105 pa and with a volume of 810102 m3 is compressed adiabatically to a volume of 450102 m3 part a part a what is the final pressur 06714
Uploaded: 2022-12-08T20:50:02-08:00
Duration: 5 min 21 s
Channel: Ivan Kochetkov
Description: a monatomic ideal gas that is initially at a pressure of 152105 pa and with a volume of 810102 m3 is compressed adiabatically to a volume of 450102 m3 part a part a what is the final pressur 06714

          A monatomic ideal gas that is initially at a pressure of 1.52×105 Pa and with a volume of 8.10×10−2 m3 is compressed adiabatically to a volume of 4.50×10−2 m3.

Part A
What is the final pressure?
P = 
  Pa 

Part B
How much work is done by the gas during the compression?
W = 
  J  

Part C
What is the ratio of the final temperature of the gas to its initial temperature?
Tf/Ti =

Added by David H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

12/08/2022

Step 1

52×10^5 Pa Initial volume, V1 = 8.10×10^-2 m^3 Final volume, V2 = 4.50×10^-2 m^3 Gamma (adiabatic index) for a monatomic gas, γ = 1.66 Using the adiabatic process equation for pressure: P2 = P1 * (V1/V2)^γ Calculating the final pressure: P2 = 1.52×10^5 * Show more…

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A monatomic ideal gas that is initially at a pressure of 1.52×105 Pa and with a volume of 8.10×10−2 m3 is compressed adiabatically to a volume of 4.50×10−2 m3. Part A What is the final pressure? P = Pa Part B How much work is done by the gas during the compression? W = J Part C What is the ratio of the final temperature of the gas to its initial temperature? Tf/Ti =