52 \times 10^{5} \mathrm{~Pa}$, the initial volume $V_1 = 7.90 \times 10^{-2} \mathrm{~m}^{3}$, and the final volume $V_2 = 4.50 \times 10^{-2} \mathrm{~m}^{3}$. We are asked to find the final pressure $P_2$. We can use the adiabatic process equation for an ideal
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