Question

A moped decelerates from a speed of 46 ft/s at a constant rate of 8 ft/s². How many seconds pass until the moped stops? That is, if we assume that $v(0) = 46$ and $a(t) = -8$ for all $t \ge 0$, then find the value of $t$ for which $v(t) = 0$. Enter the answer as a decimal number without units. Round to two decimal places.

          A moped decelerates from a speed of 46 ft/s at a constant rate of 8 ft/s². How many seconds pass until the moped stops? That is, if we assume that $v(0) = 46$ and $a(t) = -8$ for all $t \ge 0$, then find the value of $t$ for which $v(t) = 0$.
Enter the answer as a decimal number without units.
Round to two decimal places.

A moped decelerates from a speed of 46 ft/s at a constant rate of 8 ft/s². How many seconds pass until the moped stops? That is, if we assume that v(0) = 46 and a(t) = -8 for all t ≥ 0, then find the value of t for which v(t) = 0.
Enter the answer as a decimal number without units.
Round to two decimal places.

Added by Francisco S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Victor Salazar

01/22/2022

Step 1

Given v(0) = 46 ft/s and a = -8 ft/s^2, we can use the equation v(t) = 46 - 8t. Show more…

Show all steps

Thanks for your feedback!

A moped decelerates from a speed of 46f(t)/(s) at a constant rate of 8f(t)/(s^(2)). How many seconds pass until the moped stops? That is, if we assume that v(0)=46 and a(t)=-8 for all t>=0, then find the value of t for which v(t)=0. Enter the answer as a decimal number without units. Round to two decimal places. A moped decelerates from a speed of 46 ft/s at a constant rate of 8 ft/s2. How many seconds pass until the moped stops? That is, if we assume that v(0) = 46 and at=8 forall t0,then find the value of t for which v (t)0 Enter the answer as a decimal number without units. Round to two decimal places