A neutral water molecule \( \left(\mathrm{H}_{2} \mathrm{O}\right) \) in its vapor state has an electric dipole moment of magnitude \( 6.2 \times 10^{-30} \) C.m. a) How far apart are the molecule's centers of positive and negative charge? b) If the molecule is placed in an electric field of \( 1.5 \times 10^{4} \mathrm{~N} / \mathrm{C} \), what maximum torque can the field exert on it? c) How much work must an external agent do to rotate this molecule by \( 180^{\circ} \) in this field, starting from its fully aligned position, for which \( \theta=0 \) ?
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A neutral water molecule $\left(\mathrm{H}_{2} \mathrm{O}\right)$ in its vapour state has an electric dipole moment of $6 \times 10^{-30} \mathrm{Cm}$. If the molecule is placed in an electric field of $1.5 \times 10^{4} \mathrm{NC}^{-1}$, the maximum torque that the field can exert on it is nearly (a) $4.5 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (b) $4 \times 10^{-34} \mathrm{~N}-\mathrm{m}$ (c) $9 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (d) $6 \times 10^{-26} \mathrm{~N}-\mathrm{m}$
Electrostatics
Round 1
The dipole moment of the water molecule (H2O) is 6.17×10^(-30) C·m. Consider a water molecule located at the origin whose dipole moment p points in the +x-direction. A chlorine ion (Cl-), of charge -1.60 × 10^(-19) C, is located at x = 3 nm. Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used. (a) Find the magnitude of the electric force that the water molecule exerts on the chlorine ion. (b) What is the direction of the electric force? (c) Is this force attractive or repulsive?
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