A nuclear reaction of significant historical note occurred in $1932,$ when a beryllium target was bombarded with alpha particles. Analysis of the experiment indicated that the following reaction occurred: $$^{4}_2 \mathrm{He}+_{4}^{9} \mathrm{Be} \rightarrow_{6}^{12} \mathrm{C}+\mathrm{X}$$What is $X$ in this reaction? (See Sample Problem 25B.)
Added by Dolores G.
Step 1
The total atomic number (the subscript) on the left side of the equation is $2+4=6$. On the right side, we have $6$ for carbon, so the atomic number for $X$ must be $0$ to balance the equation. Show more…
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