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A parallel-plate air capacitor is to store charge of magnitude 290.0 pC on each plate when the potential difference between the plates is 44.0 V. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. Part A If the area of each plate is 6.80 cm^2, what is the separation between the plates? Express your answer with the appropriate units. d = Value mm 

          A parallel-plate air capacitor is to store charge of magnitude 290.0 pC on each plate when the potential difference between the plates is 44.0 V.
For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor.
Part A
If the area of each plate is 6.80 cm^2, what is the separation between the plates?
Express your answer with the appropriate units.
d = Value mm
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A parallel-plate air capacitor is to store charge of magnitude 290.0 pC on each plate when the potential difference between the plates is 44.0 V. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. Part A If the area of each plate is 6.80 cm^2, what is the separation between the plates? Express your answer with the appropriate units. d = Value mm

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A parallel-plate air capacitor is to store charge of magnitude 290.0 pC on each plate when the potential difference between the plates is 44.0 V Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. If the area of each plate is 6.80 cm^2, what is the separation between the plates? Express your answer with the appropriate units. d = Value mm
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Transcript

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00:01 All right, so let's say we have a parallel plate capacitor that is charged up to a voltage of 44 volts, and it has a capacitance of 29 picoculums.
00:11 Or sorry, the charge is 29 picoculums.
00:14 So we want to know if the plate area is 6 .8 square centimeters.
00:20 What's the separation between the plate? so let's write this 6 .8 times 10 to the negative 4th square meters.
00:28 Then the capacitance of the system is going to be the charge divided by the voltage difference...
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