A parallel-plate capacitor has a plate area of 0.3 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magnitude of 5 x 10^-6 C then the force exerted by one plate on the other has a magnitude of about: 0 5 N 9 x 10^5 N 9 N 1 x 10^4 N
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First, we need to find the electric field between the plates. The formula for the electric field (E) between the plates of a parallel-plate capacitor is: E = Q / (Īµā * A) where Q is the charge on each plate, Īµā is the vacuum permittivity (8.85 Ć 10ā»Ā¹Ā² CĀ²/NĀ·mĀ²), Show moreā¦
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