A parallel-plate capacitor has a plate area of 0.3 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magnitude of 5 × 10^–6 C, then the force exerted by one plate on the other has a magnitude of about:
Added by Andre H.
Step 1
Given charge on each plate = 5 × 10^–6 C Plate area = 0.3 m^2 Charge density = Total charge / Area Charge density = (5 × 10^–6 C) / (0.3 m^2) Charge density = 16.67 × 10^–6 C/m^2 Show more…
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